Support Attached
Trigonometry, please, help! You're in a hot-air balloon, with your support crew on the ground. Attached to the?
balloon are two tether cords of length 350 feet and 400 feet that your crew attached to the ground. You note that this cords form and angle of 50 degrees where they meet the balloon. Assuming these lines are taut and the ground is level, what is the distance between the points on the ground where the two tether cords are attached (rounded to one decimal place).
Solution :
let :
c = distance between 2 points
C = 50 degrees (included angle between a & b)
a = 350 ft
b = 400 ft
By Cosine Law : c^2 = a^2 + b^2 - 2abcos C
c^2 = 350^2 + 400^2 - (2 x 350 x 400 x cos 50)
c^2 = 122,500 + 160,000 - 179,980.53
c^2 = 102,519.47
c = 320.18 say 320.20 feet (Answer)
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